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Let f(x) = (2x + 1)3 · e(−x). Find f'(x) and evaluate f'(0).
You correctly applied the product rule combined with chain rule.
Let u = (2x + 1)3 and v = e(−x)
u' = 6(2x + 1)2, v' = −e(−x)
Apply product rule: f' = u'v + uv'
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